Алан Гибизов

>>> a = 2341
>>> f'{a:0>15}'
'000000000002341'

import csv

from geopy.geocoders import AlgoliaPlaces as Geo

cities = ["Токио", "Лондон", "Берлин", "Череповец"]
geo = Geo()

data = []

for i in cities:
        n = geo.geocode(i)
        data.append([i, n.latitude, n.longitude])

with open('data.csv', 'w', newline='') as f:
        w = csv.writer(f)
        w.writerow(['city', 'lat', 'lon'])
        w.writerows(data)

def sumelem(seq, step):
    for i, elem in enumerate(seq,1):
        if i%step:
            yield elem
        else:
            yield elem
            yield sum(seq[i-step:i])

print(*sumelem(a, 5))

a = [1, 2, 23, 4, 5, 6, 7, 40, 9, 10, 100, 12, 13, 14, 15, 700, 17, 18, 19, 20]

for index, group in reversed(list([(i, a[i:i+5]) for i in range(0, len(a), 5)])):
    s = sum(group)
    a.insert(index + 5, s)
    print(f'{index} {group} => {s}')

# 15 [700, 17, 18, 19, 20] => 774
# 10 [100, 12, 13, 14, 15] => 154
# 5 [6, 7, 40, 9, 10] => 72
# 0 [1, 2, 23, 4, 5] => 35

# a
# [1, 2, 23, 4, 5, 35, 6, 7, 40, 9, 10, 72, 100, 12, 13, 14, 15, 154, 700, 17, 18, 19, 20, 774]

from itertools import chain

a = [1,2,23,4,5,6,7,40,9,10,100,12,13,14,15,700,17,18,19,20]
b = list(chain(*[a[x*5:x*5+5] + [sum(a[x*5:x*5+5])] for x in range(len(a)//5)]))
print(b)

# [1, 2, 23, 4, 5, 35, 6, 7, 40, 9, 10, 72, 100, 12, 13, 14, 15, 154, 700, 17, 18, 19, 20, 774]

def generate(sequence, group_by=5, func=sum):
    for group in zip(*[iter(sequence)]*group_by):
        yield from group
        yield func(group)
        
print(*generate(a))

with open('text.txt', 'r') as f:
	import re
	print(max([len(i[0]) for i in re.findall('((XYZ)+(X|XY)?)', f.read())]))

"последний фрагмент может быть неполным"

main('C:\\Directory\\Path\\test.txt', 'C:\\Directory2\\Path\\')

main('C:/Directory/Path/test.txt', 'C:/Directory2/Path/')