JavaScript
- 171 ответ
- 0 вопросов
175
Вклад в тег
$(function() {
if ($(window).width() < 768) {
var iconset = $('.iconset-phone');
$(window).on('scroll', function() {
iconset[$(this).scrollTop() > 0 ? 'slideUp' : 'slideDown']();
});
}
});var td = $('#timeGrid td'),
selection = {
single: function(el) {
td.not(el).removeClass(this.cl);
this.ctrl(el);
},
shift: function(el) {
if (typeof this.last !== 'number') {
return this.single(el);
}
var till = $(el).index(this.slcr),
from = this.last;
if (from > till) till = [from, from = till][0];
td.not(td.eq(this.last)).removeClass(this.cl);
td.slice(from, till).add(el).addClass(this.cl);
},
ctrl: function(el) {
$(el).addClass(this.cl);
this.last = $(el).index(this.slcr);
console.log(this.last);
},
slcr: '#timeGrid td',
cl: 'pressedTime',
last: null
};
td.on('click', function(e) {
method = !e.shiftKey && !e.ctrlKey ? 'single' : (e.shiftKey ? 'shift' : 'ctrl');
selection[method](this);
});var table = $('#timeGrid'),
td = $('td', table),
selection = {
single: function(el) {
td.not(el).removeClass(this.cl);
this.ctrl(el);
},
shift: function(el) {
if (typeof this.last !== 'number') {
return this.single(el);
}
var till = $(el).index(this.slcr),
from = this.last;
if (from > till) till = [from, from = till][0];
td.not(td.eq(this.last)).removeClass(this.cl);
td.slice(from, till).add(el).addClass(this.cl);
},
ctrl: function(el) {
$(el).addClass(this.cl);
this.last = $(el).index(this.slcr);
},
slcr: '#timeGrid td',
cl: 'pressedTime',
last: null
};
var pressed = false;
td.on({
mousedown: function(e) {
method = !e.shiftKey && !e.ctrlKey ? 'single' : (e.shiftKey ? 'shift' : 'ctrl');
selection[method](this);
pressed = true;
},
mouseenter: function() {
if (pressed) {
selection.shift(this);
}
}
});
$(document).on('mouseup', '*', function(e) {
pressed = false;
});row.parentNode.insertBefore(row, row.parentNode.rows[0]);
