Обратите внимание — даже при использовании параметра offset для получения информации доступны только первые 1000 результатов.
In [1]: def x_in_bounds(x, bounds): return bounds[0] < x < bounds[1]
In [2]: if x_in_range(1, (0, 2)): print('in')
in
min_val, max_val = 1, 10
if min_val <= x <= max_val:
print("...")def BoundsChecker:
__init__(self, min_val, max_val):
self.min_val = min_val
self.max_val = max_val
def isBounded(self, val):
return self.min_val <= val <= self.max_val
checker = BoundsChecker(1, 10)
if (checker.isBounded(x))
print("...")Функция range() если я правильно понял, не удовлетворит мои потребности.
In [7]: 10 in range(1, 11)
Out[7]: True
In [8]: 1 in range(1, 11)
Out[8]: True
In [9]: 11 in range(1, 11)
Out[9]: FalseIn [12]: %timeit 5 in range(1, 11)
The slowest run took 4.69 times longer than the fastest. This could mean that an intermediate result is being cached.
1000000 loops, best of 3: 348 ns per loop
In [13]: %timeit 1 <= 5 <= 10
10000000 loops, best of 3: 60.2 ns per loop
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SET @number := 0;
SELECT
rating.*
FROM
(
SELECT
(@number := @number + 1) AS number,
user_id,
COUNT(*) AS user_commands
FROM
`log`
GROUP BY
user_id
ORDER BY
user_commands DESC
) AS rating
WHERE
rating.user_id = 2