Есть шаблон для catalog.section.list
<? if (!defined("B_PROLOG_INCLUDED") || B_PROLOG_INCLUDED !== true) die();
$this->setFrameMode(true);
?>
<div class="menu">
<div class="menu__list">
<?foreach ($arResult["SECTIONS"] as $arSection):?>
<div class="menu__item"><a class="menu__link" href="<?= $arSection["SECTION_PAGE_URL"] ?>">
<div class="menu__img">
<img class="menu__pic" src="<?=$arSection["PICTURE"]["SRC"]?>" title="<?=$arSection["NAME"]?>" border="0"/>
</div>
<div class="menu__title"><?= $arSection["NAME"] ?></div>
<svg class="menu__svg">
<use xlink:href="<?=SITE_TEMPLATE_PATH?>/images/icons/sprite.svg#angle-r"></use>
</svg></a>
</div>
<?endforeach;?>
</div>
<div class="submenu">
<a class="submenu__item" href="">Подраздел</a>
</div>
</div>
Как в div submenu вывести подразделы?