Там есть вообще все значения в т.ч. за более ранние периоды.
Я сделал так
req1=request...
soup1=bs(req1.content, 'html.parser')
result1=re.findall(re.compile(r'line1=(.*)]];'), str(soup1) ) [0] #у меня получился result1=список из одного элемента
list1=result1.split('],[')
out1
Out[133]:
['[["Dec 09 2015 01: +0",7.989,"44"',
'"Dec 10 2015 01: +0",5.743,"66"',
'"Dec 11 2015 01: +0",5.277,"73"',
'"Dec 12 2015 01: +0",5.262,"89"',
'"Dec 13 2015 01: +0",4.953,"66"',
'"Dec 14 2015 01: +0",4.65,"80"',
'"Dec 15 2015 01: +0",6.189,"67"',
'"Dec 16 2015 01: +0",4.673,"53"',
'"Dec 17 2015 01: +0",4.55,"44"',
'"Dec 18 2015 01: +0",4.458,"53"',
'"Dec 19 2015 01: +0",4.419,"61"',
.....
'"Aug 30 2022 07: +0",1.709,"2"',
'"Aug 30 2022 09: +0",1.67,"1"',
'"Aug 30 2022 10: +0",0.203,"1"',
'"Aug 30 2022 12: +0",1.748,"1"',
'"Aug 30 2022 13: +0",1.75,"2"',
'"Aug 30 2022 14: +0",1.708,"2"',
'"Aug 30 2022 18: +0",1.1,"2"',
'"Aug 30 2022 20: +0",1.776,"1"',
'"Aug 30 2022 21: +0",1.745,"2"',
'"Aug 30 2022 22: +0",1.61,"1"',
'"Aug 30 2022 23: +0",1.847,"1"',
'"Aug 31 2022 02: +0",1.63,"1"',
'"Aug 31 2022 03: +0",1.82,"2"',
'"Aug 31 2022 04: +0",1.58,"1"',
'"Aug 31 2022 06: +0",1.58,"1"',
'"Aug 31 2022 10: +0",1.24,"1"',
'"Aug 31 2022 11: +0",1.897,"1"',
'"Aug 31 2022 13: +0",1.58,"1"',
'"Aug 31 2022 14: +0",1.854,"2"',
'"Aug 31 2022 15: +0",1.41,"1"']
len(out1)
Out[134]: 2816