madmages
@madmages
Человек прямоходящий

Где ошибка в sql запросе?

. "SELECT"
            . "  pd.name    as name,"
            . "  p.G_ide    as id,"
            . "  p.model    as articul,"
            . "  pa.`value` as sort,"
            . "  p.upc      as code_1C,"
            . "  p.status   as status,"
            . "  pts.price  as price,"
            . "  p.market   as market,"
            . "  'product'  as type,"
            . "  c.category_id as category,"
            . "  c.skpath as skpath,"
            . "  (SELECT 1 FROM product WHERE height=0 AND length=0 AND width=0 AND product_id=pts.product_id) as gab,"
            . "  (SELECT name FROM category_description WHERE category_id=c.category_id AND language_id=2) as category_name,"
            . "  p1c.data   as data_1c"
            . " FROM"
            . "   category c"
            . " LEFT JOIN"
            . "  product_to_category ptc ON (ptc.category_id=c.category_id)"
            . " LEFT JOIN"
            . "  product p ON (ptc.product_id=p.product_id)"
            . " LEFT JOIN"
            . "  product_description pd ON (pd.product_id=p.product_id)"
            . " LEFT JOIN"
            . "  product_to_store pts ON (pts.product_id=p.product_id)"
            . " LEFT JOIN"
            . "  product_additional pa ON (pa.product_id=p.product_id)"
            . " LEFT JOIN"
            . "  product_1c p1c ON p1c.product_id=p.product_id"
            . " UNION " //--------------------
            . "'' as name,"
            . " del.delimiter_id as id,"
            . " '' as articul,"
            . " '' as sort,"
            . " '' as code_1C,"
            . " '' as status,"
            . " '' as price,"
            . " '' as market,"
            . " 'delim'  as type,"
            . " '' as category,"
            . " '' as skpath,"
            . " '' as gab,"
            . " '' as category_name,"
            . " '' as data_1c"
            . " FROM"
            . "  delimiter del"
            . " LEFT JOIN"
            . "  delimiter_description deld ON (del.delimiter_id = deld.delimiter_id) "
            . " LEFT JOIN "
            . "  delimiter_to_category d2c ON (del.delimiter_id = d2c.delimiter_id) "
            . " LEFT JOIN "
            . "  category dc ON (dc.category_id = d2c.category) "
            . " UNION " //--------------------
            . "  ccd.name as name, "
            . "  cc.category_id as id, "
            . "  '' as articul, "
            . "  '' as sort, "
            . "  '' as code_1C, "
            . "  '' as status, "
            . "  '' as price, "
            . "  '' as market, "
            . "  cctc.type  as type, "
            . "  '' as category, "
            . "  '' as skpath, "
            . "  '' as gab, "
            . "  '' as category_name, "
            . "  '' as data_1c "
            . " FROM "
            . "  category cc "
            . " LEFT JOIN "
            . "  category_description ccd ON (ccd.category_id = cc.category_id) "
            . " LEFT JOIN "
            . "  category_to_category cctc ON (cctc.to = cc.category_id) "
            . " WHERE  pa.`key`=concat('sort_',c.category_id) AND pd.language_id=2 AND cc.parent_id=".(int)$category_id." AND dc.parent_id=".(int)$category_id." AND c.parent_id=" . (int)$category_id;


coбственно вот. ругается что неправильный синтаксис в районе UNION '' AS name, del.delimiter_id AS id
но неверного синтаксиса в упор не вижу
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Решения вопроса 1
UNION [ALL | DISTINCT] SELECT ...

UNION '' AS name
union что? Может SELECT '' AS name ...
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Ответы на вопрос 1
qmax
@qmax
программер
Мощно!
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