Akina

SELECT MIN(`min_price`) OVER () as `min_price`, 
       MAX(`max_price`) OVER () as `max_price`, 
       `item_id` as `id`
FROM `product_table` 
WHERE `id` IN (SELECT  тут запрос)

Akina, да, версия 5.7.21 и она, я так понимаю, не поддерживает оконные функции.

SELECT t2.min_price, 
       t2.max_price, 
       t1.item_id as id
FROM product_table t1
CROSS JOIN ( SELECT MIN(min_price) AS min_price, 
             MAX(max_price) AS max_price
             FROM product_table ) t2
WHERE t1.id IN (SELECT  тут запрос)

SELECT CASE WHEN sender_id = 1
            THEN receiver_id
            ELSE sender_id 
            END AS buddy
FROM message
WHERE 1 IN (sender_id, receiver_id)
GROUP BY buddy
ORDER BY MAX(sent_at)

SELECT user.username
FROM user
JOIN ( SELECT CASE WHEN sender_id = 1
                   THEN receiver_id
                   ELSE sender_id 
                   END AS id,
              MAX(sent_at) sent_at
       FROM message
       WHERE 1 IN (sender_id, receiver_id)
       GROUP BY 1 ) ids USING (id)
ORDER BY ids.sent_at

SELECT DISTINCT
       key,
       FIRST_VALUE(value1) OVER (PARTITION BY key 
                                 ORDER BY CASE WHEN value1 IS NULL 
                                               THEN 1 
                                               ELSE 0 END, id DESC) AS value1,
       FIRST_VALUE(value2) OVER (PARTITION BY key 
                                 ORDER BY CASE WHEN value2 IS NULL 
                                               THEN 1 
                                               ELSE 0 END, id DESC) AS value2,
       FIRST_VALUE(value3) OVER (PARTITION BY key 
                                 ORDER BY CASE WHEN value3 IS NULL 
                                               THEN 1 
                                               ELSE 0 END, id DESC) AS value3
FROM tablename
-- WHERE key IN ( {список значений} )

переписать таблицу в нормальную форму

SELECT orders.column,
       COALESCE(books.column, deposits.column) AS column
FROM orders 
LEFT JOIN books ON orders.type = 'book' AND orders.id = books.order_id
LEFT JOIN deposits ON orders.type = 'deposit' AND orders.id = deposits.order_id

call_id, где есть больше одного значение value

SELECT call_id
FROM tablename
GROUP BY call_id
HAVING COUNT(DISTINCT value) > 1