Нашел вот такой код для SSH-ловушки (honeypot).
В 16ой строке выводится username и password, с которым пытались подключиться.
Мне необходимо, чтобы в этой строке выводился еще и IP клиента
#!/usr/bin/env python3
import socket, sys, threading
import paramiko
# from threading import Thread
#generate keys with 'ssh-keygen -t rsa -f server.key'
HOST_KEY = paramiko.RSAKey(filename='./server.key')
SSH_PORT = 22
class SSHServerHandler (paramiko.ServerInterface):
def __init__(self):
self.event = threading.Event()
def check_auth_password(self, username, password):
print("New login: " + username + ":" + password) # <-16ая СТРОКА
return paramiko.AUTH_FAILED
def get_allowed_auths(self, username):
return 'password'
def handleConnection(client):
transport = paramiko.Transport(client)
transport.add_server_key(HOST_KEY)
server_handler = SSHServerHandler()
transport.start_server(server=server_handler)
channel = transport.accept(1)
if not channel is None:
channel.close()
def main():
try:
server_socket = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
server_socket.setsockopt(socket.SOL_SOCKET, socket.SO_REUSEADDR, 1)
server_socket.bind(('', SSH_PORT))
server_socket.listen(100)
# paramiko.util.log_to_file ('paramiko.log')
while(True):
try:
client_socket, client_addr = server_socket.accept()
threading.Thread(target=handleConnection, args=(client_socket,)).start()
# thread.start_new_thread(handleConnection,(client_socket,))
except Exception as e:
print("ERROR: Client handling")
print(e)
except Exception as e:
print("ERROR: Failed to create socket")
print(e)
sys.exit(1)
main()
