i!=j && a[i]==a[j] && a[i] > A
for (i=0; i<N; i++) {
float a[i] = {4, 3, 1, 9, 1, -4, -1, 4, -4, 3, 9, -1, 18, 14, 18, 7};
printf("%d ", a[i]);
count++;
}
float c = 1.0 / 5* x * y + sqrt((exp(x - 1) + exp(y - 1)) / (cos(x+2*y)*cos(x + 2 * y)));