У меня возникла проблема, я пробую запустить самое легкое, а оно не видит этого...
URLS.PY
from django.conf.urls import url
from django.contrib import admin
urlpatterns = [
url(r'^admin/', admin.site.urls),
url(r'^', index.views),
]
VIEWS.PY
from __future__ import absolute_import, unicode_literals
from django.core.urlresolvers import reverse
from django.views.generic import DetailView, ListView, RedirectView, UpdateView
from django.contrib.auth.mixins import LoginRequiredMixin
from .models import User
from django.shortcusts import render
from django.http import HttpResponse
def index(request):
return HttpResponse("<h1></h1>")
class UserDetailView(LoginRequiredMixin, DetailView):
model = User
# These next two lines tell the view to index lookups by username
slug_field = 'username'
slug_url_kwarg = 'username'
class UserRedirectView(LoginRequiredMixin, RedirectView):
permanent = False
def get_redirect_url(self):
return reverse('users:detail',
kwargs={'username': self.request.user.username})
class UserUpdateView(LoginRequiredMixin, UpdateView):
fields = ['name', ]
# we already imported User in the view code above, remember?
model = User
# send the user back to their own page after a successful update
def get_success_url(self):
return reverse('users:detail',
kwargs={'username': self.request.user.username})
def get_object(self):
# Only get the User record for the user making the request
return User.objects.get(username=self.request.user.username)
class UserListView(LoginRequiredMixin, ListView):
model = User
# These next two lines tell the view to index lookups by username
slug_field = 'username'
slug_url_kwarg = 'username'
Консоль < Unhandled exception in thread started by
Traceback (most recent call last):
File "/Library/Python/2.7/site-packages/django/utils/autoreload.py", line 226, in wrapper
fn(*args, **kwargs)
File "/Library/Python/2.7/site-packages/django/core/management/commands/runserver.py", line 121, in inner_run
self.check(display_num_errors=True)
File "/Library/Python/2.7/site-packages/django/core/management/base.py", line 374, in check
include_deployment_checks=include_deployment_checks,
File "/Library/Python/2.7/site-packages/django/core/management/base.py", line 361, in _run_checks
return checks.run_checks(**kwargs)
File "/Library/Python/2.7/site-packages/django/core/checks/registry.py", line 81, in run_checks
new_errors = check(app_configs=app_configs)
File "/Library/Python/2.7/site-packages/django/core/checks/urls.py", line 14, in check_url_config
return check_resolver(resolver)
File "/Library/Python/2.7/site-packages/django/core/checks/urls.py", line 24, in check_resolver
for pattern in resolver.url_patterns:
File "/Library/Python/2.7/site-packages/django/utils/functional.py", line 35, in __get__
res = instance.__dict__[self.name] = self.func(instance)
File "/Library/Python/2.7/site-packages/django/urls/resolvers.py", line 313, in url_patterns
patterns = getattr(self.urlconf_module, "urlpatterns", self.urlconf_module)
File "/Library/Python/2.7/site-packages/django/utils/functional.py", line 35, in __get__
res = instance.__dict__[self.name] = self.func(instance)
File "/Library/Python/2.7/site-packages/django/urls/resolvers.py", line 306, in urlconf_module
return import_module(self.urlconf_name)
File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/importlib/__init__.py", line 37, in import_module
__import__(name)
File "/Users/Mark/Firstapp/Firstapp/urls.py", line 21, in
url(r'^', index.views),
NameError: name 'index' is not defined >
У меня в коде не видит index
