Есть проект, в нем 2 папки
backend - symfony для api
frontend - angular
По дефолту всё должно идти в index.html но вот запросы
mydomain.by/api/*****
уже должны идти в бэкент.
Долго ковырялся, накидал вот такой вроде бы даже рабочий конфиг для nginx
server {
listen 80;
listen [::]:80;
server_name mydomain.by;
location / {
root /var/www/mydomain/frontend/dist;
index index.html;
rewrite ^(/)/$ $1 permanent;
try_files $uri /index.html$is_args$args;
}
location ~ ^/(api|ping$) {
root /var/www/mydomain/backend/web;
# try to serve file directly, fallback to app.php
try_files $uri /app.php$is_args$args;
}
location ~ ^/app\.php(/|$) {
root /var/www/mydomain/backend/web;
fastcgi_pass unix:/run/php/php7.1-fpm.sock;
fastcgi_split_path_info ^(.+\.php)(/.*)$;
include fastcgi_params;
# When you are using symlinks to link the document root to the
# current version of your application, you should pass the real
# application path instead of the path to the symlink to PHP FPM.
# Otherwise, PHP's OPcache may not properly detect changes to
# your PHP files (see https://github.com/zendtech/ZendOptimizerPlus/issues/126
# for more information).
fastcgi_param SCRIPT_FILENAME $realpath_root$fastcgi_script_name;
fastcgi_param DOCUMENT_ROOT $realpath_root;
# Prevents URIs that include the front controller. This will 404:
# http://domain.tld/app.php/some-path
# Remove the internal directive to allow URIs like this
internal;
}
# return 404 for all other php files not matching the front controller
# this prevents access to other php files you don't want to be accessible.
location ~ \.php$ {
return 404;
}
}
Есть у кого мысли как это сделать правельнее ?
