Как сделать так, чтобы бот удалял свое предпоследнее сообщение? (Aiogram, Python)?

Question

[SKEiLTreeeeS]

Допустим, бот отправил в канал одно сообщение, всего в канале сейчас одно сообщение, потом бот отправляет второе сообщение, спустя время и, чтобы не засорять канал, он должен удалить предыдущее сообщение и оставить свежее!

Comments

[SKEiLTreeeeS]

from aiogram import Bot, Dispatcher, executor, types
import time

Token = "5962272909:AAEXM4bM-JmDlL0hhjUl75HMU8FQYqDssA8"
bot = Bot(token=Token)
dp = Dispatcher(bot=bot)
isDelieved = True

MSG = "Привет"
MSG2 = "hi"

@dp.message_handler(commands='test')
async def test(message: types.message):
user_id = message.from_user.id
n = 1
a = 1
b = 0
if n == a:
await MSG2.delete()
await bot.send_message(MSG)
n = b
time.sleep(5)
if n == b:
await MSG.delete()
await bot.send_message(MSG2)

if __name__ == '__main__':
executor.start_polling(dp)

[SKEiLTreeeeS]

from aiogram import Bot, Dispatcher, executor, types
import time

Token = "5962272909:AAEXM4bM-JmDlL0hhjUl75HMU8FQYqDssA8"
bot = Bot(token=Token)
dp = Dispatcher(bot=bot)
isDelieved = True

MSG = "Привет"
MSG2 = "hi"

@dp.message_handler(commands='test')
async def test(message: types.message):
    user_id = message.from_user.id
    n = 1
    a = 1
    b = 0
    if n == a:
        await MSG2.delete()
        await bot.send_message(MSG)
        n = b
        time.sleep(5)
    if n == b:
        await MSG.delete()
        await bot.send_message(MSG2)

if __name__ == '__main__':
    executor.start_polling(dp)

[SKEiLTreeeeS]

Yokaze, Не писал это даже

Answer 1

[Fqwd123]

from telegram.ext import Updater, CommandHandler
import logging

# Enable logging
logging.basicConfig(format='%(asctime)s - %(name)s - %(levelname)s - %(message)s',
                    level=logging.INFO)
logger = logging.getLogger(__name__)

# Your bot's token
TOKEN = 'YOUR_BOT_TOKEN'

# The chat id of the channel
CHAT_ID = 'YOUR_CHAT_ID'

# Create a TelegramBot object
bot = TelegramBot(TOKEN)

# Define a function that sends a message to the channel and deletes the previous message
def send_message(bot, update, message):
    # Send the message
    sent_message = bot.send_message(chat_id=CHAT_ID, text=message)

    # Delete the previous message
    bot.delete_message(chat_id=CHAT_ID, message_id=sent_message.message_id - 1)

# Create an Updater object
updater = Updater(TOKEN)

# Create a CommandHandler to handle the '/send' command
send_handler = CommandHandler('send', send_message)

# Add the send_handler to the dispatcher
updater.dispatcher.add_handler(send_handler)

# Start the bot
updater.start_polling()

Answer 2

[blacksmithIT]

await bot.delete_message()