Видает ошибку Error binding parameter 1 — probably unsupported type. что делать?

Question

[vomir]

Что не так ?

@bot.message_handler(commands=['start'])
def start(message):
    sql = sqlite3.connect('C:\\Program1\\bot.telegram\\bazdan.db3')
    c = sql.cursor()
    c.execute("""CREATE TABLE IF NOT EXISTS user (id INTEGER, name TEXT, race, inventory)""")
    sql.commit()
    sql.close

@bot.message_handler(content_types=['text'])
def history_now(message):
    if message.chat.type == 'private':
        user_id=[message.chat.id]
        c.execute(f"SELECT race FROM user WHERE id == ?",(user_id))
        data=c.fetchone()
        if data is not None:
            name=message.text
            c.execute(f"UPDATE user SET name =? WHERE id=?", (name, user_id))
            sql.commit()
            sql.close
            confirm_name=(f'Имя {name} записано')
            bot.send_message(message.chat.id, confirm_name, parse_mode='html')

вот сама ошибка
c.execute(f"UPDATE user SET name =? WHERE id=?", (name, user_id))
sqlite3.InterfaceError: Error binding parameter 1 - probably unsupported type.

Answer 1

[vomir]

вот так работает

@bot.message_handler(content_types=['text'])
def history_now(message):
    if message.chat.type == 'private':
       <b> user_id=message.chat.id</b>
        c.execute(f"SELECT race FROM user WHERE <b>id={user_id}</b>",)
        data=c.fetchone()
        if data is not None:
            name=message.text
            c.execute(f"UPDATE user SET name =? WHERE id=?",(name, user_id) )
            sql.commit()
            sql.close
            confirm_name=(f'Имя {name} записано')
            bot.send_message(message.chat.id, confirm_name, parse_mode='html')