Почему не работает мой код на django в файле models.py?

Question

[Semechka1290]

Написал я такой код:

import datetime
from django.db import models

from django.utils import timezone

class Article(models.Model):
    title = models.CharField('Название статьи', max_length=200)
    text = models.TextField('Текст статьи', max_length=200)
    pub = models.DateTimeField('Дата публикации', max_length=200)

    def __str__(self):
        return self.title

    def publish(self):
        return self.pub_date >= (timezone.now() - datetime.timedelta(days = 7))
        
class Comment(models.Model):
    article = models.ForeignKey(Article, on_delete = models.CASCADE)
    author = models.CharField('Имя автора', max_length=20)
    text = models.CharField('Текст комментария', max_length=200)

    def __str__(self):
        return self.author

Сначала я захожу в Коммандную строку, и пишу:

1) python manage.py shell
2) from articles import Article, Comment
3) a = Article.objects.get(id  = 1)

И после 3-ей этой строчки появляется ошибка:

spoiler

Если что я делал миграции

Traceback (most recent call last):
  File "C:\Users\vue\AppData\Local\Programs\Python\Python310\lib\site-packages\django\db\backends\utils.py", line 89, in _execute
    return self.cursor.execute(sql, params)
  File "C:\Users\vue\AppData\Local\Programs\Python\Python310\lib\site-packages\django\db\backends\sqlite3\base.py", line 477, in execute
    return Database.Cursor.execute(self, query, params)
sqlite3.OperationalError: no such column: articles_article.pub

The above exception was the direct cause of the following exception:

Traceback (most recent call last):
  File "<console>", line 1, in <module>
  File "C:\Users\vue\AppData\Local\Programs\Python\Python310\lib\site-packages\django\db\models\manager.py", line 85, in manager_method
    return getattr(self.get_queryset(), name)(*args, **kwargs)
  File "C:\Users\vue\AppData\Local\Programs\Python\Python310\lib\site-packages\django\db\models\query.py", line 492, in get
    num = len(clone)
  File "C:\Users\vue\AppData\Local\Programs\Python\Python310\lib\site-packages\django\db\models\query.py", line 302, in __len__
    self._fetch_all()
  File "C:\Users\vue\AppData\Local\Programs\Python\Python310\lib\site-packages\django\db\models\query.py", line 1507, in _fetch_all
    self._result_cache = list(self._iterable_class(self))
  File "C:\Users\vue\AppData\Local\Programs\Python\Python310\lib\site-packages\django\db\models\query.py", line 57, in __iter__
    results = compiler.execute_sql(
  File "C:\Users\vue\AppData\Local\Programs\Python\Python310\lib\site-packages\django\db\models\sql\compiler.py", line 1361, in execute_sql
    cursor.execute(sql, params)
  File "C:\Users\vue\AppData\Local\Programs\Python\Python310\lib\site-packages\django\db\backends\utils.py", line 103, in execute
    return super().execute(sql, params)
  File "C:\Users\vue\AppData\Local\Programs\Python\Python310\lib\site-packages\django\db\backends\utils.py", line 67, in execute
    return self._execute_with_wrappers(
  File "C:\Users\vue\AppData\Local\Programs\Python\Python310\lib\site-packages\django\db\backends\utils.py", line 80, in _execute_with_wrappers
    return executor(sql, params, many, context)
  File "C:\Users\vue\AppData\Local\Programs\Python\Python310\lib\site-packages\django\db\backends\utils.py", line 84, in _execute
    with self.db.wrap_database_errors:
  File "C:\Users\vue\AppData\Local\Programs\Python\Python310\lib\site-packages\django\db\utils.py", line 91, in __exit__
    raise dj_exc_value.with_traceback(traceback) from exc_value
  File "C:\Users\vue\AppData\Local\Programs\Python\Python310\lib\site-packages\django\db\backends\utils.py", line 89, in _execute
    return self.cursor.execute(sql, params)
  File "C:\Users\vue\AppData\Local\Programs\Python\Python310\lib\site-packages\django\db\backends\sqlite3\base.py", line 477, in execute
    return Database.Cursor.execute(self, query, params)
django.db.utils.OperationalError: no such column: articles_article.pub
>>>

Что делать?