Как можно спарсить все img src?

Question

[0b88111450d12ec15c9628]

На странице десятки таких блоков, нужно спарсить все img src=

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Comments

[Рамис]

>>> from bs4 import BeautifulSoup
>>> html = """<div><img src=""></div><div><img src=""></div>"""
>>> bs = BeautifulSoup(html, 'html.parser')
>>> img = bs.find_all('img')
>>> img
[<img src=""/>, <img src=""/>]

[AVKor]

https://www.w3schools.com/html/html_id.asp

The id attribute specifies a unique id for an HTML element. The value of the id attribute must be unique within the HTML document.

Answer 1

[Андрей Баранов]

Установить BeautifulSoup
pip install beautifulsoup4

Документация https://pypi.org/project/beautifulsoup4/

from bs4 import BeautifulSoup
 
with open("index.html", "r") as f:
    
    contents = f.read()
 
    soup = BeautifulSoup(contents, 'lxml')
 
    for tag in soup.find_all("img"):
        print("{0}: {1}".format(tag.name, tag.text))