Ошибка "VkNet.Exception.ParameterMissingOrInvalidException visual studio windows forms c# VK API.Как исправить?

Question

[killman]

создал программу которая должна принимать фотографию с компьютера и выкладывать её в сообщество ВКонтакте.Но при компиляции выдаёт ошибку VkNet.Exception.ParameterMissingOrInvalidException: "One of the parameters specified was missing or invalid: invalid message param"
Вот мой код:
using System;
using System.Collections.Generic;
using System.ComponentModel;
using System.Data;
using System.Drawing;
using System.Linq;
using System.Text;
using System.Threading.Tasks;
using System.Windows.Forms;
using System.IO;
using System.Net;
using VkNet;
using VkNet.Model;
using System.Threading;
using xNet;
using Newtonsoft.Json;
using Newtonsoft.Json.Linq;
using VkNet.Model.Attachments;

namespace Vkner_test
{

public partial class Form1 : Form
{
public string post_ID;
WebClient client = new WebClient();
public VkApi api = new VkApi();
long owner_id = -211976873;
string message = "Всем привет, это тест VK API";
ulong appID = 8110264;
string login1;
string password;
authorization auth = new authorization();

List attachments = new List();

OpenFileDialog openFileDialog = new OpenFileDialog();
Uri file;

public Form1()
{

InitializeComponent();


}

private void Form1_Load(object sender, EventArgs e)
{

}

private void button1_Click(object sender, EventArgs e)
{



attachments.Add(new Photo
{

Url = file,

});





api.Wall.Post(new VkNet.Model.RequestParams.WallPostParams
{
OwnerId = owner_id,
FriendsOnly = false,
FromGroup = true,
// Message = message,


Attachments = attachments,

});


}

private void button2_Click(object sender, EventArgs e)
{
//auth.ShowDialog();
//error.Text = api.Token;


try
{
api.Authorize(new ApiAuthParams
{
AccessToken = *******
});

error.Text = "";
}
catch (VkNet.Exception.VkAuthorizationException)
{

error.Text = "Неверный логин или пароль";

}

}

private void button3_Click(object sender, EventArgs e)
{
var openfile = openFileDialog.ShowDialog();

if (openfile == DialogResult.OK)
{
file = new Uri(openFileDialog.FileName);
}
}
}
}