Иван Чуркин

SELECT id 
    FROM places p
    JOIN (
        SELECT place_id 
            FROM example 
            WHERE equi_id IN (1, 2, 3)
            GROUP BY place_id
            HAVING COUNT(place_id) = 3
        ) e ON e.place_id = p.id
    WHERE p.param1 = 1 AND p.param2 = 2