PHP
1
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<form action="POST" enctype="multipart/form-data" >
<input type="file" id="input__file">
<form>
var $input = $('#input__file');
var fd = new FormData;
fd.append('excel', $input.prop('files')[0]);
$.ajax({
url: '/center/ajax-file/',
data: fd,
processData: false,
contentType: false,
type: 'POST',
success: function (data) {
console.log(data)
}
});