Как спарсить ссылку на видео?

Question

[opsimecom]

Здравствуйте! Есть скрипт парсера написанный на питоне, как спарсить видео ?
пробую так :

try:
        fb_video = block.find('source', class_='video-player').get(
            'src')
        # print(fb_video)
    except Exception as er:
        # print(er)
        fb_video = ' '

Не получается....

А вот код html код

<div class="video-player"><video preload="metadata" class="video-player__video"><source src="https://275129.selcdn.ru/macaw/da9f8edbf08737a6358a.mp4" type="video/mp4"></video><div class="video-player__controls"><div class="video-player__control video-player__control--play"><div type="button" class="video-player__play"></div></div><div class="video-player__control video-player__control--progress-bar"><div class="video-player__progress-bar"><div class="video-player__buffer-value" style="width: 99.3798%;"></div><div class="video-player__progress-value" style="width: 10.0246%;"></div></div></div><div class="video-player__control video-player__control--time"><div class="video-player__time">-0:22</div></div><div class="video-player__control video-player__control--mute"><div class="video-player__mute"></div></div><div class="video-player__control video-player__control--fullscreen"><div class="video-player__fullscreen"></div></div></div></div>

Спарсить надо ссылку

Answer 1

[Evgeniy _]

У вас у source нет класса video-player.

Это bs4?
Попробуйте:

vids = block.findAll('source')

for vid in vids:
    vid['src']

Comments

[opsimecom]

сделал так : try:
fb_video = block.find('a', class_='banner-media-unit__action banner-media-unit__action--media-download').get('download')
# print(fb_video)
except Exception as er:
# print(er)
fb_video = ' '
Всем спасибо

Answer 2

[meeshanya]

Вот такой вариант может быть рабочим:
fb_video = block.find("source", href=True ).attrs['href']