Как в Spring из FilterChain отправить ModelAndView?

Question

[Евгений Краснов]

Приветствую уважаемые форумчане.

Подскажите пожалуйста, как из фильтра вернуть ModelAndView. Редирект сделать можно, а вот вернуть ModelAndView , как то не получается.

Буду очень признателен за помощь.

package com.test;

import org.springframework.stereotype.Component;
import org.springframework.web.filter.GenericFilterBean;

import javax.servlet.FilterChain;
import javax.servlet.ServletException;
import javax.servlet.ServletRequest;
import javax.servlet.ServletResponse;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
import java.io.IOException;

@Component
public class Test extends GenericFilterBean {

    @Override
    public void doFilter(ServletRequest request, ServletResponse response, FilterChain chain) throws IOException, ServletException {


        HttpServletRequest httpServletRequest = (HttpServletRequest) request;
        HttpServletResponse httpServletResponse = (HttpServletResponse) response;
        
        
        httpServletResponse.sendRedirect(httpServletRequest.getContextPath() + "/test");
        
            chain.doFilter(request, response);

    }

}

Answer 1

[Орхан Гасанлы]

Думаю, что вот тут ответ на ваш вопрос -
https://stackoverflow.com/questions/3616763/settin...
В частности:

i think this is not possible, because this is a servlet filter, which would be applied after the spring request mapper servlet was applied. so basically, the request mapper servlet thinks it is finished, and passes the request back to the servlet container.
view names only work INSIDE of spring - outside of spring, in the servlet container, you will have to talk about urls, not view names.