Как разбить список логов в питоне?

Question

[Andrei Sayevich]

Из такого списка

logi = [
    '2019-01-01,user0,3',
    '2019-01-07,user0,4',
    '2019-03-29,user0,1',
    '2019-04-04,user0,13',
    '2019-01-05,user1,7',
    '2019-06-14,user2,4',
    '2019-07-02,user2,10',
    '2019-03-21,user3,19',
    '2019-03-22,user3,4',
    '2019-04-22,user3,8',
    '2019-05-03,user3,9',
    '2019-05-11,user3,11',
]

в примерно такой

logi = [
    ["2019-01-01","user0","3"],
    ["2019-01-07","user0","4"],
    ["2019-03-29","user0","1"],
    ["2019-04-04","user0","13"],
    ["2019-01-05","user1","7"],
    ["2019-06-14","user2","4"],
    ["2019-07-02","user2","10"],
    ["2019-03-21","user3","19"],
    ["2019-03-22","user3","4"],
    ["2019-04-22","user3","8"],
    ["2019-05-03","user3","9"],
    ["2019-05-11","user3","11"],
]

Comments

[Andrei Sayevich]

logi = [
    ["2019-01-01","user0","3"],
    ["2019-01-07","user0","4"],
    ["2019-03-29","user0","1"],
    ["2019-04-04","user0","13"],
    ["2019-01-05","user1","7"],
    ["2019-06-14","user2","4"],
    ["2019-07-02","user2","10"],
    ["2019-03-21","user3","19"],
    ["2019-03-22","user3","4"],
    ["2019-04-22","user3","8"],
    ["2019-05-03","user3","9"],
    ["2019-05-11","user3","11"],
]

окей .. а теперь это как преобразовать в ....


logi =
[[2019-01-01],[user0],[3]],
[[2019-01-07],[user0],[4]],
[[2019-03-29],[user0],[1]],
[[2019-04-04],[user0],[13]],
[[2019-01-05],[user1],[7]],
[[2019-06-14],[user2],[4]],
[[2019-07-02],[user2],[10]],
[[2019-03-21],[user3],[19]],
[[2019-03-22],[user3],[4]],
[[2019-04-22],[user3],[8]],
[[2019-05-03],[user3],[9]],
[[2019-05-11],[user3],[11]],
]

Answer 1

[ScriptKiddo]

[x.split(',') for x in logi]

Comments

[Andrei Sayevich]

я не совсем понял как это работает.
функция .split заменяет "," на " , " но это же не делает список состоящий из списков )

[ScriptKiddo]

Andrei Sayevich, Можете почитать об этом здесь https://docs.python.org/3/tutorial/datastructures....