Как вывести alt в xslt umi?

Question

[Junior Coder]

Как вывести alt? Изображение без alt выводится?

<img src="/images/cms/thumbs/a47f0b7da6923bed8a792d31599e28712d335ad7/istra_plani_1et_395_auto_0_80.jpg" width="395" height="395">

<xsl:template name="mini-photo-2">
		<xsl:param name="img" select="0"/>
		<xsl:param name="rel" select="0"/>
		<xsl:param name="alt" />
		<xsl:if test="$img/value !=''">
			<li>
				<a class="group2" href="{$img/value}">
					<xsl:call-template name="thumbnail-project">
						<xsl:with-param name="element-id" select="1" />
						<xsl:with-param name="src"><xsl:value-of select="$img/value" /></xsl:with-param>
						<xsl:with-param name="empty">&empty-photo;</xsl:with-param>
						<xsl:with-param name="width">395</xsl:with-param>
						<xsl:with-param name="alt" select="$alt" />
					</xsl:call-template>
				</a>
			</li>
		</xsl:if>
	</xsl:template>

Answer 1

[i]

<xsl:call-template
    name = "mini-photo-2">
    <xsl:with-param name="img" select="piv.pmg"/>
    <xsl:with-param name="alt" select="alt"/>
</xsl:call-template>

Подробнее xsl:call-template и xsl:with-param.