У меня есть такая таблица
+------------+------------+------------+
| id | price | date |
+------------+------------+------------+
| 1 | 3000 | 2019-01-26 |
| 2 | 2500 | 2019-01-23 |
| 3 | 2000 | 2019-01-22 |
| 4 | 3000 | 2019-01-21 |
+------------+------------+------------+
Мне нужно, добавить все недостающие даты и присвоить им цены. При выводе на php
+------------+------------+------------+
| id | price | date |
+------------+------------+------------+
| 100 | 3000 | 2019-01-28 |
| 100 | 3000 | 2019-01-27 |
| 100 | 3000 | 2019-01-26 |
| 100 | 2500 | 2019-01-25 |
| 100 | 2500 | 2019-01-24 |
| 100 | 2500 | 2019-01-23 |
| 100 | 2000 | 2019-01-22 |
| 100 | 3000 | 2019-01-21 |
+------------+------------+------------+
Я пытаюсь и делаю так, но естественно он выводит только то, что уже есть в базе
$sql = "SELECT products.id_lab, products.vendor, products.vendor_code, products.name, products.author, products.description, products.image_product, products.link_product, prices.price_product, prices.date AS max_date
FROM products
LEFT OUTER JOIN prices ON products.id_lab = prices.id_lab
WHERE prices.price_product != 0 AND products.id_lab = '".$row_product['id_lab']."'
ORDER BY prices.date DESC, prices.price_product DESC;";
$result = mysqli_query($link,$sql);
foreach($result as $article1) {
if (isset($article1['price_product'])) {
$articles2[date("d.m.Y",strtotime($article1['max_date']))] = (int)$article1['price_product'];
}
}
foreach($result as $article2) {
if (isset($article1['price_product'])) {
$articles1[date("d.m.Y",strtotime($article2['max_date']))] = (int)$article2['price_product'];
}
}