Здравствуйте. Помогите, пожалуйста, подключить к моему прилложение spring-security.
Итак, я:
1) Прописал фреймворк в pom, web.
2) Первая страница, которая будет открываться (с формой логина и пароля) -index.jsp
c формой
<div class="col-sm-6 col-md-4 col-lg-3" style="margin:40px auto; float:none;">
<form method="post" action="/main">
<c:url var="loginUrl" value="/j_spring_security_check"></c:url>
<div class="col-xs-12">
<div class="form-group">
<div class="input-group">
<div class="input-group-addon"><i class="fa fa-fw fa-user"></i></div>
<input type="email" name="j_username" class="form-control" placeholder="E-mail">
</div>
</div>
<div class="form-group">
<div class="input-group">
<div class="input-group-addon"><i class="fa fa-fw fa-lock"></i></div>
<input type="password" name="j_password" class="form-control" placeholder="Password">
</div>
</div>
</div>
3) Пользователи и пароли хранятся в базе. Настройки spring-security.xml
<?xml version="1.0" encoding="UTF-8"?>
<beans:beans xmlns="http://www.springframework.org/schema/security"
xmlns:beans="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:tx="http://www.springframework.org/schema/tx"
xmlns:context="http://www.springframework.org/schema/context"
xsi:schemaLocation="http://www.springframework.org/schema/security http://www.springframework.org/schema/security/spring-security.xsd
http://www.springframework.org/schema/tx http://www.springframework.org/schema/tx/spring-tx-4.0.xsd
http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans.xsd http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context.xsd">
<beans:import resource="appServlet/servlet-context.xml"/>
<!-- Configuring RoleVoter bean to use custom access roles, by default roles
should be in the form ROLE_{XXX} -->
<beans:bean id="roleVoter"
class="org.springframework.security.access.vote.RoleVoter">
<beans:property name="rolePrefix" value=""></beans:property>
</beans:bean>
<beans:bean id="accessDecisionManager"
class="org.springframework.security.access.vote.AffirmativeBased">
<beans:constructor-arg name="decisionVoters"
ref="roleVoter"/>
</beans:bean>
<http realm="JavaStudy example" use-expressions="false"
authentication-manager-ref="dao-auth"
access-decision-manager-ref="accessDecisionManager">
<intercept-url pattern="/main" access="ROLE_USER,ROLE_ANONYMOUS"/>
<intercept-url pattern="/user/*" access="ROLE_USER"/>
<intercept-url pattern="/admin/*" access="ROLE_ADMIN"/>
<form-login login-page="/index" default-target-url="/main"
authentication-failure-url="/login.jsp?error=true"/>
<logout logout-url="/logout" logout-success-url="/main"/>
<anonymous username="guest" granted-authority="ROLE_ANONYMOUS"/>
</http>
<authentication-manager>
<authentication-provider>
<user-service>
<user name="admin" password="admin" authorities="ROLE_USER, ROLE_ADMIN"/>
<user name="user" password="user" authorities="ROLE_USER"/>
<user name="guest" password="guest" authorities="ROLE_GUEST"/>
</user-service>
</authentication-provider>
</authentication-manager>
<authentication-manager id="dao-auth">
<authentication-provider user-service-ref="userDetailsService">
<password-encoder ref="passwordEncoder"/>
</authentication-provider>
</authentication-manager>
<beans:bean id="passwordEncoder"
class="operator.utils.Converter">
</beans:bean>
</beans:beans>
4) В контролере имею
@RequestMapping(value = "/main", method = RequestMethod.GET)
public String dispatch(HttpServletRequest request, Locale locale, Model model) {
org.springframework.security.core.userdetails.User user = (org.springframework.security.core.userdetails.User)
SecurityContextHolder.getContext().getAuthentication().getPrincipal();
User currentUser = userService.getUserByEMAil(user.getUsername());
request.getSession().setAttribute("currentUserU", currentUser);
request.getSession().setAttribute("language", RussianLanguage.getRussianLanguage());
if (currentUser.getAccessLevel().getAccessLevelId() == 1) {
return "user/index";
}
else if (currentUser.getAccessLevel().getAccessLevelId() == 3){
return "admin/index";
}
else return "index";
}
5) Организовал проверку пароля по хешу в Converter
Однако при прохождении формы получаю шибку
Could not verify the provided CSRF token because your session was not found.
Что я делаю не так?
Простой
