>Нужно выбрать из таблицы такие object_id, option_id которых равны одновременно нескольким значениям.
select o.object_id as object_id
from object_option o
INNER JOIN object_option o2 on o2.object_id = o.object_id
WHERE o2.option_id != o.option_id
GROUP BY o.object_id
