Как распарсить скрипт JS при помощи phpQuery?

Question

[Данил]

Имеется вот такой код

hlsList: {"1080":"https://m1.rumer.club/manifest/MTc4LjE1OS4yMTYuMTQy/?video=https%3A%2F%2Fhls-t001-l001-c086-s001.intravideo.net%2F04_01_20%2F04%2F01%2F16%2FAYLFV5VV%2FAVEHPEEI.mp4%2Ftracks%2Fv1-a%2Fmaster.m3u8",
"480":"https://m1.rumer.club/manifest/MTc4LjE1OS4yMTYuMTQy/?video=https%3A%2F%2Fhls-t001-l001-c086-s001.intravideo.net%2F04_01_20%2F04%2F01%2F16%2FAYLFV5VV%2FAVEHPEEI.mp4%2Ftracks%2Fv2-a%2Fmaster.m3u8",
"720":"https://m1.rumer.club/manifest/MTc4LjE1OS4yMTYuMTQy/?video=https%3A%2F%2Fhls-t001-l001-c086-s001.intravideo.net%2F04_01_20%2F04%2F01%2F16%2FAYLFV5VV%2FAVEHPEEI.mp4%2Ftracks%2Fv1-a%2Fmaster.m3u8"}

Нужно получить ссылку для качества 720

Answer 1

[Stalker_RED]

phpQuery не нужен.

$str = 'hlsList: {"1080":"https://m1.rumer.club/manifest/MTc4LjE1OS4yMTYuMTQy/?video=https%3A%2F%2Fhls-t001-l001-c086-s001.intravideo.net%2F04_01_20%2F04%2F01%2F16%2FAYLFV5VV%2FAVEHPEEI.mp4%2Ftracks%2Fv1-a%2Fmaster.m3u8",
"480":"https://m1.rumer.club/manifest/MTc4LjE1OS4yMTYuMTQy/?video=https%3A%2F%2Fhls-t001-l001-c086-s001.intravideo.net%2F04_01_20%2F04%2F01%2F16%2FAYLFV5VV%2FAVEHPEEI.mp4%2Ftracks%2Fv2-a%2Fmaster.m3u8",
"720":"https://m1.rumer.club/manifest/MTc4LjE1OS4yMTYuMTQy/?video=https%3A%2F%2Fhls-t001-l001-c086-s001.intravideo.net%2F04_01_20%2F04%2F01%2F16%2FAYLFV5VV%2FAVEHPEEI.mp4%2Ftracks%2Fv1-a%2Fmaster.m3u8"}';

$json = str_replace('hlsList: ', '', $str);
$links = json_decode($json, true);
echo $links['720'];