Проблемы с gulp?

Question

[Анатолий Тароев]

Суть Вопроса:
Пытался настроить Gulp при подключении плагина gulp-file-include
и вызова через командную строку " Gulp "
вылетает такая ошибка!
PS C:\Users\Admin\Desktop\fls_gulp> gulp
TypeError: Assignment to constant variable.
at Object. (C:\Users\Admin\Desktop\fls_gulp\gulpfile.js:33:17)
at Module._compile (internal/modules/cjs/loader.js:1133:30)
at Object.Module._extensions..js (internal/modules/cjs/loader.js:1153:10)
at Module.load (internal/modules/cjs/loader.js:977:32)
at Function.Module._load (internal/modules/cjs/loader.js:877:14)
at Module.require (internal/modules/cjs/loader.js:1019:19)
at require (internal/modules/cjs/helpers.js:77:18)
at requireOrImport (C:\Users\Admin\AppData\Roaming\npm\node_modules\gulp-cli\lib\shared\require-or-import.js:19:11)
at execute (C:\Users\Admin\AppData\Roaming\npm\node_modules\gulp-cli\lib\versioned\^4.0.0\index.js:37:3)
at Liftoff.handleArguments (C:\Users\Admin\AppData\Roaming\npm\node_modules\gulp-cli\index.js:211:24)
Удалять папку node_modules и файл package-lock пробовал не помагает.

Comments

[Михаил]

когда вы научитесь ошибки читать?
Assignment to constant variable

[approximate solution]

Кидайте сюда весь ваш код из gulpfile.js

[Анатолий Тароев]

approximate solution,
const fileinclude = require('gulp-file-include');

let project_folder = "dist";
let source_folder = "#src";

let path = {
build: {
html: project_folder + "/",
css: project_folder + "/css/",
js: project_folder + "/js/",
img: project_folder + "/img/",
fonts: project_folder + "/fonts/",
},
src: {
html: source_folder + "/*.html",
css: source_folder + "/css/style.css",
js: source_folder + "/js/script.js",
img: source_folder + "/img/**/*.{jpg,png,gif,ico,webp}",
fonts: source_folder + "/fonts/*.ttf",
},
watch: {
html: source_folder + "/**/*.html",
css: source_folder + "/css/**/*.css",
js: source_folder + "/js/**/*.js",
img: source_folder + "/img/**/*.{jpg,png,gif,ico,webp}"
},
clean: "./" + project_folder + "/"
}

let { src, dest } = require('gulp'),
gulp = require('gulp'),
browsersync = require("browser-sync").create();
fileinclude = require("gulp-file-include");

function browserSync(params) {
browsersync.init({
server: {
baseDir: "./" + project_folder + "/"
},
port: 3000,
notify: false
})
}

function html() {
return src(path.src.html)
.pipe(fileinclude())
.pipe(dest(path.build.html))
.pipe(browsersync.stream())
}

let build = gulp.series(html);
let watch = gulp.parallel(build,browserSync);

exports.html = html;
exports.build = build;
exports.watch = watch;
exports.default = watch;

[Александр]

Анатолий Тароев, const fileinclude = require('gulp-file-include'); и fileinclude = require("gulp-file-include");. Ничего не смущает?

[Анатолий Тароев]

Александр, SyntaxError: Identifier 'fileinclude' has already been declared
at wrapSafe (internal/modules/cjs/loader.js:1047:16)
at Module._compile (internal/modules/cjs/loader.js:1097:27)
at Object.Module._extensions..js (internal/modules/cjs/loader.js:1153:10)
at Module.load (internal/modules/cjs/loader.js:977:32)
at Function.Module._load (internal/modules/cjs/loader.js:877:14)
at Module.require (internal/modules/cjs/loader.js:1019:19)
at require (internal/modules/cjs/helpers.js:77:18)
at requireOrImport (C:\Users\Admin\AppData\Roaming\npm\node_modules\gulp-cli\lib\shared\require-or-import.js:19:11)
at execute (C:\Users\Admin\AppData\Roaming\npm\node_modules\gulp-cli\lib\versioned\^4.0.0\index.js:37:3)
at Liftoff.handleArguments (C:\Users\Admin\AppData\Roaming\npm\node_modules\gulp-cli\index.js:211:24)

[Александр]

Анатолий Тароев, Так все верно, у Вас дважды объявляется эта переменная.

[Анатолий Тароев]

Александр, тю блин )))
спасибо большое все запустилось.