Как исправить ошибку?

Question

[Yourmind]

Как исправить ошибку Caused by: org.postgresql.util.PSQLException: ERROR: relation "users" does not exist?

таблица для клиентов:

@Entity
@Table(name = "Users")
public class User {
    @Id
    private String login;
    private String phone;
    //ссылка на фото
    private String photo;
   @ManyToMany
    @JoinTable(name = "USER_Advertisement",
            joinColumns = { @JoinColumn(name = "login") },
            inverseJoinColumns = { @JoinColumn(name = "id") })
    private Set<Advertisement> cart = new HashSet<>();
    public User( String login, String phone, String photo) {
        this.login = login;
        this.phone = phone;
        this.photo = photo;
    }
    @OneToMany
    private Set<Advertisement> advertisements = new HashSet<>();
}

таблица для клиентов:

<spoiler title="репозиторий:"><code>
@Repository
public  interface  UserRepository extends CrudRepository<User, String> {
     //сохранить клиента
    User save(User user);
   ...
}
</code></spoiler>
<spoiler title="пытаюсь совершить:"><code>
@SpringBootApplication
public class NedoAvitoApplication implements ApplicationRunner {
    @Autowired
	UserRepository rec;
	public static void main(String[] args) {

		SpringApplication.run(NedoAvitoApplication.class, args);

	}

	@Override
	public void run(ApplicationArguments args) throws Exception {
		User a=new User("k", "ko", "gggggu");
         	rec.save(a);
	}
}
</code></spoiler>
Но на строке rec.save(a): Caused by: org.postgresql.util.PSQLException: ERROR: relation "users" does not exist  
<spoiler title="в настройках стоит автоматом создавать таблицы:"><code>
spring.datasource.url= jdbc:postgresql://localhost:5432/mydate 
spring.datasource.username=test_user
spring.datasource.password=ххх
spring.datasource.driverClassName=org.postgresql.Driver

logging.level.org.hibernate=DEBUG

spring.jpa.hibernate.ddl-auto=create
spring.jpa.properties.hibernate.show_sql=true
spring.jpa.properties.javax.persistence.schema-generation.scripts.create-target=target/my-schema.sql
spring.jpa.properties.javax.persistence.schema-generation.scripts.action=create
javax.persistence.schema-generation.scripts.action=create
</code></spoiler>