Изучаю Си. Написал простенький конвертер времени. Оцените его пожалуйста
//Конвертер временных значений
#include<stdio.h>
#define A_PER_B 60 //константа значения
int main(void)
{
int sec, min, hor, left, input;//объявление переменных
printf("Welcome in time converter!\n");
printf("For continue press any key and 0 for exit\n");
scanf_s("%d", &input);
while (input != 0)
{
printf("Choose mode\n");
printf("1.Sec to min\n2.Min to hor\n3.Hor to min\n4.Min to sec\n5.Exit\n");
scanf_s("%d", &input);//выбор режима конвертера
switch (input)
{
case 1:
printf("Enter quantity sec\n");
scanf_s("%d", &sec);
while (sec > 0)
{
min = sec / A_PER_B;//операция нахождения минут
left = sec%A_PER_B;//остаток секунд
printf("%d sec is %d min and %d sec\n", sec, min, left);
printf("Enter next value(Enter 0 for exit!)\n");
scanf_s("%d", &sec);//ввод нового значения, либо выход из цикла
}
break;
case 2:
printf("Enter quantity min\n");
scanf_s("%d", &min);
while (min > 0)
{
hor = min / A_PER_B;
left = min%A_PER_B;//остаток секунд
printf("%d min is %d hor and %d min\n", min, hor, left);
printf("Enter next value(Enter 0 for exit!)\n");
scanf_s("%d", &min);
}
break;
case 3:
printf("Enter quantity hour\n");
scanf_s("%d", &hor);
while (hor > 0)
{
min = hor*A_PER_B;
printf("%d hor is %d min\n", hor, min);
printf("Enter next value(Enter 0 for exit!)\n");
scanf_s("%d", &hor);
}
break;
case 4:
printf("Enter quantity min\n");
scanf_s("%d", &min);
while (min > 0)
{
sec = min*A_PER_B;
printf("%d min is %d sec\n", min, sec);
printf("Enter next value(Enter 0 for exit!)\n");
scanf_s("%d", &min);
}
break;
case 5:
printf("Have a nice day!Goodbye!\n");
return(0);
}
}
printf("Ready!\n");
return(0);
}