Пишу Spring-приложение, которое должно взаимодействовать с БД.
У меня есть контекст приложения:
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:p="http://www.springframework.org/schema/p"
xmlns:c="http://www.springframework.org/schema/c"
xmlns:context="http://www.springframework.org/schema/context"
xmlns:util="http://www.springframework.org/schema/util"
xsi:schemaLocation="http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans.xsd
http://www.springframework.org/schema/context
http://www.springframework.org/schema/context/spring-context.xsd
http://www.springframework.org/schema/util
http://www.springframework.org/schema/util/spring-util.xsd
">
<bean id="dataSource" class="org.springframework.jdbc.datasource.DriverManagerDataSource">
<property name="driverClassName" value="com.mysql.jdbc.Driver" />
<property name="url" value="jdbc:mysql://localhost/PersonManager" />
<property name="username" value="root" />
<property name="password" value="12345" />
</bean>
<!-- Проблема с инжектом этого бина :/ -->
<bean id="emf" class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean">
<property name="dataSource" ref="dataSource" />
<property name="packagesToScan" value="com.slandshow" />
<property name="jpaVendorAdapter">
<bean class="org.springframework.orm.jpa.vendor.HibernateJpaVendorAdapter">
<property name="showSql" value="true" />
<property name="database" value="MYSQL" />
<property name="databasePlatform" value="org.hibernate.dialect.MySQL5Dialect" />
</bean>
</property>
</bean>
<bean class="org.springframework.orm.jpa.support.PersistenceAnnotationBeanPostProcessor" />
<bean id="studentDao" class="com.slandshow.dao.StudentDao" />
</beans>
Имею следующие зависимости в pom
<?xml version="1.0" encoding="UTF-8"?>
<project xmlns="http://maven.apache.org/POM/4.0.0"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://maven.apache.org/POM/4.0.0 http://maven.apache.org/xsd/maven-4.0.0.xsd">
<modelVersion>4.0.0</modelVersion>
<groupId>com.slandshow</groupId>
<artifactId>javaschoolproject</artifactId>
<version>1.0-SNAPSHOT</version>
<packaging>war</packaging>
<properties>
<spring.framework.version>3.1.3.RELEASE</spring.framework.version>
<mysql.connector.version>5.1.21</mysql.connector.version>
<hiberate.version>4.3.5.Final</hiberate.version>
<hibernate.annotation.version>3.5.6-Final</hibernate.annotation.version>
</properties>
<dependencies>
<dependency>
<groupId>org.springframework</groupId>
<artifactId>spring-core</artifactId>
<version>${spring.framework.version}</version>
</dependency>
<dependency>
<groupId>org.springframework</groupId>
<artifactId>spring-beans</artifactId>
<version>${spring.framework.version}</version>
</dependency>
<dependency>
<groupId>org.springframework</groupId>
<artifactId>spring-context</artifactId>
<version>${spring.framework.version}</version>
</dependency>
<dependency>
<groupId>org.springframework</groupId>
<artifactId>spring-jdbc</artifactId>
<version>${spring.framework.version}</version>
</dependency>
<dependency>
<groupId>org.springframework</groupId>
<artifactId>spring-orm</artifactId>
<version>${spring.framework.version}</version>
</dependency>
<dependency>
<groupId>mysql</groupId>
<artifactId>mysql-connector-java</artifactId>
<version>${mysql.connector.version}</version>
</dependency>
<dependency>
<groupId>org.hibernate</groupId>
<artifactId>hibernate-core</artifactId>
<version>${hibernate.version}</version>
</dependency>
<dependency>
<groupId>org.hibernate</groupId>
<artifactId>hibernate-annotations</artifactId>
<version>${hibernate.annotation.version}</version>
</dependency>
<dependency>
<groupId>org.hibernate</groupId>
<artifactId>hibernate-entitymanager</artifactId>
<version>${hiberate.version}</version>
</dependency>
</dependencies>
</project>
И теперь, вот что у меня есть.
DAO:
package com.slandshow.dao;
import com.slandshow.model.Student;
import org.springframework.stereotype.Repository;
import javax.persistence.EntityManager;
import javax.persistence.PersistenceContext;
import java.util.List;
@Repository
public class StudentDao implements BaseDao<Student> {
@PersistenceContext
protected EntityManager emf;
public List<Student> findAll(){
return emf.createQuery("from students").getResultList();
}
}
package com.slandshow.model;
import javax.persistence.Column;
import javax.persistence.Entity;
import javax.persistence.Id;
import javax.persistence.Table;
import java.io.Serializable;
/*
* id (INTEGER PRIMARY KEY)
* name (VARCHAR)
* class (VARCHAR)
*/
@Entity(name = "students")
@Table(name = "Students")
public class Student implements Serializable {
@Id
@Column(name = "id")
protected long id;
@Column(name = "name")
protected String name;
@Column(name = "class")
protected String clazz; // class name reserved, so i use clazz...
public void setId(long id) {
this.id = id;
}
public void setName(String name) {
this.name = name;
}
public void setClazz(String clazz) {
this.clazz = clazz;
}
@Override
public String toString() {
return "Student{" + "id=" + id + ", name=" + name + ", class=" + clazz + '}';
}
}
model
package com.slandshow.model;
import javax.persistence.Column;
import javax.persistence.Entity;
import javax.persistence.Id;
import javax.persistence.Table;
import java.io.Serializable;
/*
* id (INTEGER PRIMARY KEY)
* name (VARCHAR)
* class (VARCHAR)
*/
@Entity(name = "students")
@Table(name = "Students")
public class Student implements Serializable {
@Id
@Column(name = "id")
protected long id;
@Column(name = "name")
protected String name;
@Column(name = "class")
protected String clazz; // class name reserved, so i use clazz...
public void setId(long id) {
this.id = id;
}
public void setName(String name) {
this.name = name;
}
public void setClazz(String clazz) {
this.clazz = clazz;
}
@Override
public String toString() {
return "Student{" + "id=" + id + ", name=" + name + ", class=" + clazz + '}';
}
}
И точка входа в приложение:
package com.slandshow;
import com.slandshow.dao.StudentDao;
import com.slandshow.model.Student;
import org.springframework.context.ApplicationContext;
import org.springframework.context.support.ClassPathXmlApplicationContext;
import java.util.List;
public class App {
public static void main(String... args) {
ApplicationContext ctx = (ApplicationContext)new ClassPathXmlApplicationContext("app-context.xml");
StudentDao studentDao = (StudentDao) ctx.getBean("studentDao");
List<Student> list = studentDao.findAll();
for (Student student: list) {
System.out.println(student);
}
}
}
При запуске у меня ошибка создания бина
emf(лог ниже, но он неполный)
Exception in thread "main" org.springframework.beans.factory.BeanCreationException: Error creating bean with name 'emf' defined in class path resource [app-context.xml]: Cannot create inner bean 'org.springframework.orm.jpa.vendor.HibernateJpaVendorAdapter#6bdf28bb' of type [org.springframework.orm.jpa.vendor.HibernateJpaVendorAdapter] while setting bean property 'jpaVendorAdapter'; nested exception is org.springframework.beans.factory.BeanCreationException: Error creating bean with name 'org.springframework.orm.jpa.vendor.HibernateJpaVendorAdapter#6bdf28bb' defined in class path resource [app-context.xml]: Instantiation of bean failed; nested exception is org.springframework.beans.BeanInstantiationException: Could not instantiate bean class [org.springframework.orm.jpa.vendor.HibernateJpaVendorAdapter]: Constructor threw exception; nested exception is java.lang.NoClassDefFoundError: org/hibernate/internal/CoreMessageLogger
at org.springframework.beans.factory.support.BeanDefinitionValueResolver.resolveInnerBean(BeanDefinitionValueResolver.java:282)
at org.springframework.beans.factory.support.BeanDefinitionValueResolver.resolveValueIfNecessary(BeanDefinitionValueResolver.java:121)
....
.........
Не понимаю - что тут не так?
Простой
Простой
