Почему сервер не принимает значение переменной?

Question

[sunnyrio]

taskOpen.php:

<?php
require_once 'dy_functions.php';
$j = $_POST['msg'];
$result = queryMysql( 'SELECT * FROM task WHERE idt="$j"');
echo json_encode($result);
?>

ajax:

function taskOpen(i)
{
	$.ajax({
     url: "taskOpen.php",
	 data: { msg: i },
	 method: "post",
	 type: "json",
     success:  function(date) { 
$("#wintask").prepend("<div class='subtask'>"
+date.theader
+date.tprice
+date.ttext+"</div>");}
 })
}

Answer 1

[sunnyrio]

<?php
require_once 'dy_functions.php';
$j = $_POST['msg'];
$result = queryMysql("SELECT * FROM task WHERE idt='$j'");
$msg = $result->fetch_array( MYSQLI_ASSOC );
echo json_encode($msg);
?>