Как сделать постоянный обмен между сервером и клиентом(браузер)?
Сейчас на сервере запускаю вот такой код
<?php
// prevent the server from timing out
set_time_limit(0);
// include the web sockets server script (the server is started at the far bottom of this file)
require 'class.PHPWebSocket.php';
// when a client sends data to the server
function wsOnMessage($clientID, $message, $messageLength, $binary) {
global $Server;
$ip = long2ip( $Server->wsClients[$clientID][6] );
// check if message length is 0
if ($messageLength == 0) {
$Server->wsClose($clientID);
return;
}
//The speaker is the only person in the room. Don't let them feel lonely.
if ( sizeof($Server->wsClients) == 1 )
$Server->wsSend($clientID, "There isn't anyone else in the room, but I'll still listen to you. --Your Trusty Server");
else
//Send the message to everyone but the person who said it
foreach ( $Server->wsClients as $id => $client )
if ( $id != $clientID )
$Server->wsSend($id, "Visitor $clientID ($ip) said \"$message\"");
}
// when a client connects
function wsOnOpen($clientID)
{
global $Server;
$ip = long2ip( $Server->wsClients[$clientID][6] );
$Server->log( "$ip ($clientID) has connected." );
//Send a join notice to everyone but the person who joined
foreach ( $Server->wsClients as $id => $client )
if ( $id != $clientID )
$Server->wsSend($id, "Visitor $clientID ($ip) has joined the room.");
}
// when a client closes or lost connection
function wsOnClose($clientID, $status) {
global $Server;
$ip = long2ip( $Server->wsClients[$clientID][6] );
$Server->log( "$ip ($clientID) has disconnected." );
//Send a user left notice to everyone in the room
foreach ( $Server->wsClients as $id => $client )
$Server->wsSend($id, "Visitor $clientID ($ip) has left the room.");
}
// start the server
$Server = new PHPWebSocket();
$Server->bind('message', 'wsOnMessage');
$Server->bind('open', 'wsOnOpen');
$Server->bind('close', 'wsOnClose');
// for other computers to connect, you will probably need to change this to your LAN IP or external IP,
// alternatively use: gethostbyaddr(gethostbyname($_SERVER['SERVER_NAME']))
$Server->wsStartServer('127.0.0.1', 9300);
?>
Сервер стартует, клиенты в браузере видят сообщения
<!doctype html>
<html>
<head>
<meta charset='UTF-8' />
<style>
input, textarea {border:1px solid #CCC;margin:0px;padding:0px}
#body {max-width:800px;margin:auto}
#log {width:100%;height:400px}
#message {width:100%;line-height:20px}
</style>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.7.1/jquery.min.js"></script>
<script src="fancywebsocket.js"></script>
<script>
var Server;
function log( text ) {
$log = $('#log');
//Add text to log
$log.append(($log.val()?"\n":'')+text);
//Autoscroll
$log[0].scrollTop = $log[0].scrollHeight - $log[0].clientHeight;
}
function send( text ) {
Server.send( 'message', text );
}
$(document).ready(function() {
log('Connecting...');
Server = new FancyWebSocket('ws://127.0.0.1:9300');
$('#message').keypress(function(e) {
if ( e.keyCode == 13 && this.value ) {
log( 'You: ' + this.value );
send( this.value );
$(this).val('');
}
});
//Let the user know we're connected
Server.bind('open', function() {
log( "Connected." );
});
//OH NOES! Disconnection occurred.
Server.bind('close', function( data ) {
log( "Disconnected." );
});
//Log any messages sent from server
Server.bind('message', function( payload ) {
log( payload );
});
Server.connect();
});
</script>
</head>
<body>
<div id='body'>
<textarea id='log' name='log' readonly='readonly'></textarea><br/>
<input type='text' id='message' name='message' />
</div>
</body>
</html>
Вопрос-
Как на стороне сервера отправить в сокет сообщение(идеаkьно через php), что-бы его увидели клиенты?
Средний