Как пользоваться аннотацией JPA @Query?

Question

ddddd tttt @pashaa

Spring

Как пользоваться аннотацией JPA @Query?

package Service;

import Entitys.Contact;
import org.jboss.logging.Param;
import org.springframework.data.jpa.repository.JpaRepository;
import org.springframework.data.jpa.repository.Query;
import org.springframework.scheduling.annotation.Async;

/**
 * Created by D$DA$E on 14.01.2017.
 */
public interface ContactRepository extends JpaRepository<Contact,Long> {

    @Query("select d from Entitys.Contact d where d.id = :id")
    Contact findById(@Param("id") Long id);

}

package Entitys;

import org.hibernate.annotations.Type;
import org.springframework.format.annotation.DateTimeFormat;

import javax.persistence.*;

import java.io.Serializable;
import java.text.SimpleDateFormat;
import java.util.Date;

import static javax.persistence.GenerationType.IDENTITY;

/**
 * Created by D$DA$E on 14.01.2017.
 */
@Entity
@Table(name = "contact")
public class Contact implements Serializable {
    private Long id;
    private int version;
    private String firstName;
    private String lastName;
    private Date birthDate;
    private String description;
    private byte[] photo;

    @Id
    @GeneratedValue(strategy = IDENTITY)
    @Column(name = "ID")
        public Long getid() {return id;}
        public void setid (Long id) {this. id = id;}
    @Version
    @Column(name = "VERSION")
        public int getVersion() {return version;}
        public void setVersion(int version) {this.version = version;}

    @Column(name = "FIRST_NAJ1E")
        public String getFirstName() {return firstName;}
        public void setFirstName(String firstName) {this.firstName = firstName;}

    @Column(name = "LAST_NAМE")
        public String getLastName() {return lastName;}
        public void setLastName(String lastName) {this.lastName = lastName;}

    @Column(name = "BIRTH_DATE")
    @Type(type="org.jadira.usertype.dateandtime.joda.PersistentDateTime")
    @DateTimeFormat(iso= DateTimeFormat.ISO.DATE)
        public Date getBirthDate() {return birthDate;}
        public void setBirthDate(Date birthDate) {this.birthDate = birthDate;}

    @Column (name = "DESCRIPTION")
        public String getDescription() {return description;}
        public void setDescription(String description) {this.description = description;}

    @Basic(fetch= FetchType.LAZY)
    @Lob
    @Column(name = "РНОТО")
        public byte [] getPhoto () {return photo;}
        public void setPhoto (byte [] photo) {this.photo = photo;}

    @Transient
        public String getBirthDateString() {
    String birthDateString = "";
        SimpleDateFormat simpleDateFormat = new SimpleDateFormat("yyyy-MM-dd");
     if (birthDate != null)
     birthDateString = simpleDateFormat.format(birthDate);
     return birthDateString;
    }

        @Override
        public String toString(){
    return "Contact - Id: " + id + ", First name: " + firstName
                + ", Last name: " + lastName + ", Birthday: " + birthDate
                + ", Description: " + description;}
}

Contact находиться в каталоге Entitys,а ContactRepository в Service
Почему d.id can't resolve symbol 'id' , @Param перечеркнут и ошибка found String, required Class<?>