Здравствуйте. Мне невообразимо стыдно показывать такое, но времени переделывать нет.
Проблема: метод set_city не видит метод db_row_update. Ошибка следующая:
Fatal error: Uncaught Error: Call to undefined function db_row_update() in C:\server\Apache24\htdocs\livemasters\User.php:104
Вот сам класс:
class User{
public function __construct($id){
$this->id = $id;
$this->load();
}
public function load(){
if(!isset($this->id) || (int)$this->id == 0){
return false;
}
$mysqli = db_connect();
$current_id = $mysqli->real_escape_string($this->id);
$req = "SELECT u.ID, u.name, u.age, u.city_id, c.city_name FROM users AS u INNER JOIN cities AS c ON (c.city_id = u.city_id) WHERE u.ID = $current_id";
echo $req;
$res = $mysqli->query($req);
if($res !== false){
if($res->num_rows == 1 ){
while($row = $res ->fetch_assoc()){
$this-> id = $row['ID'];
$this-> username = $row['name'];
$this-> city_name = $row['city_name'];
$this-> city_id = $row['city_id'];
$this-> age = $row['age'];
}
} else return false;
} else return false;
}
public static function GetAllUsers(){
$mysqli = db_connect();
$req = 'SELECT u.id, u.Name, u.age, c.city_name FROM users AS u INNER JOIN cities AS c ON (c.city_id = u.city_id) ORDER BY u.ID LIMIT 25';
$result=$mysqli->query($req);
if($result !== false) {
if($result->num_rows !== 0) {
return $result;
} else echo 'table users is empty';
} else echo 'something went wrong';
}
private $username;
private $city_name;
private $city_id;
private $id;
private $age;
private function db_row_update($col_name, $value){
$mysqli = db_connect();
$value = $mysqli->real_escape_string($value);
$request = "UPDATE users SET $col_name='$value' WHERE ID=$this->id";
$result = $mysqli->query($request);
if($result){
if($col_name == 'city_id'){
$result->free();
$request = 'SELECT city_name FROM cities WHERE city_id = $value';
$result = $mysqli->query($request);
while($row = $result->fetch_row()){
$city_name = $row[0];
break;
}
return $city_name;
} else return true;
} else return false;
}
public function set_name($value){
$this->username = $value;
if($this ->db_row_update('name', $value)) return true;
else return false;
}
public function set_age($value){
$this->age = $value;
if($this->db_row_update('age', $value)) return true;
else return false;
}
public function set_city($value){
$this->city_id = $value;
$name = db_row_update('city_id', $value);
if(is_string($name)){
$this->city_name = $name;
return true;
} else return false;
}
public function getName(){
return $this->username;
}
public function getAge(){
return $this->age;
}
public function getCityName(){
return $this->city_name;
}
public function getID(){
return $this->id;
}
public function getCityId(){
return $this->city_id;
}
}
Я грешил на то, что функция db_row_update может не находится из-за того, что в зависимости от результата она возвращает значения разных типов. Удалил все, связанное с этим, но проблема не исчезла. Как быть?
