Как убрать ошибку [Browsersync] Reloading Browsers... (buffered 2 events)?

Question

[CaMo3JIO]

const { src, dest, watch, parallel} = require('gulp');
const sass           = require('gulp-sass')(require('sass'));
const concat         = require('gulp-concat');
const autoprefixer   = require('gulp-autoprefixer');
const uglify         = require('gulp-uglify');
const browserSync    = require('browser-sync').create();



function browsersync() {
  browserSync.init({
    server:{
      baseDir: 'app/'
    }
  })
  
}

function styles() {
  return src('scss/style.scss')
    .pipe(sass({outputStyle: 'compressed'}))
    .pipe(concat('style.mis.css'))
    .pipe(autoprefixer({
      overrideBrowserslist: ['last 10 version'],
      grid: true
    }))
    .pipe(dest('app/css'))
    .pipe(browserSync.stream())
}

function scripts() {
  return src([
   'node_modules/jquery/dist/jquery.js', 
   'app/js/main.js'  
  ])
  .pipe(concat('main.min.js'))
    .pipe(uglify())
    .pipe(dest('app/js'))
    .pipe(browserSync.stream()) 
  };



function watching() {
  watch(['scss/**/*.scss'],styles);
  watch(['app/js/**/*.js', '!app/js/main.min.js'], scripts);
  watch(['app/**/*.html']).on('cheange', browserSync.reload);
}

exports.styles = styles;
exports.scripts = scripts;
exports.browsersync = browsersync;
exports.watching = watching;

exports.default = parallel(styles, scripts, browsersync, watching)

Comments

[Сергей delphinpro]

с чего вы взяли, что это ошибка?