Нужно изменить код, чтобы в нем не было express.
Подскажите пожалуйста как можно сделать это
const express = require("express");
const bcrypt = require ('bcrypt');
const fs = require('fs');
const app = express();
const urlencodedParser = express.urlencoded({extended: false});
function createHash(userPassword) {
const salt = bcrypt.genSaltSync(10);
const hash = bcrypt.hashSync(userPassword, salt);
return {
hash,
salt,
}
}
function checkUser(userName, userPassword) {
const data = fs.readFileSync('users.txt', 'utf-8');
const users = []
data.split(';').forEach(item => {
if (!item.length) return
const [userName, hash] = item.split(' ')
users.push({
userName,
hash
})
})
const currentUser = users.find(item => item.userName === userName)
if (!currentUser) {
const { hash, salt } = createHash(userPassword)
const newData = `${data}${userName} ${hash} ${salt};`
fs.writeFileSync('users.txt', newData, 'utf-8');
return true
}
return bcrypt.compareSync(Buffer.from(userPassword), currentUser.hash)
}
app.use(express.static(__dirname));
app.get("/", function (request, response) {
response.sendFile(__dirname + "/index.html");
});
app.post("/", urlencodedParser, function (request, response) {
const { userName, userPassword } = request?.body || {}
if (!userName ||
userName === '' ||
!userPassword ||
userPassword == '' ||
/\s/g.test(userName)
) {
return response.sendStatus(400);
}
const isLoggedIn = checkUser(userName, userPassword)
if (!isLoggedIn) response.sendStatus(400)
response.sendStatus(200)
});
app.listen(3000, () => console.log('Server work'));
