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  • Как получить все изменённые файлы в конкретной ревизии svn?

    @bighoc Автор вопроса
    php/javascript developer
    #!/bin/bash
    
    if [ ! $1 ] || [ ! $2 ]; then
        echo "Please enter a revision from, revision to, SVN repository, and target directory"
        exit
    fi
    
    # set up nice names for the incoming parameters to make the script more readable
    revision_from=$1
    revision_to=$2
    repository=$3
    target_directory='export/r'${1}'-r'${2}
    
    # the grep is needed so we only get added/modified files and not the deleted ones or anything else
    # if it's a modified directory it's " M" so won't show with this command (good)
    # if it's an added directory it's still "A" so will show with this command (not so good)
    
    for line in `svn diff --summarize -r$revision_from:$revision_to $repository | grep "^[AM]"`
    do
        # each line in the above command in the for loop is split into two:
        # 1) the status line (containing A, M, AM, D etc)
        # 2) the full repository and filename string
        # so only export the file when it's not the status line
        if [ $line != "A" ] && [ $line != "AM" ] && [ $line != "M" ]; then
            # use sed to remove the repository from the full repo and filename
            filename=`echo "$line" |sed "s|$repository||g"`
            # don't export if it's a directory we've already created
            if [ ! -d $target_directory$filename ]; then
                directory=`dirname $filename`
                mkdir -p $target_directory$directory
                svn export -r $revision_to $line $target_directory$filename
            fi
        fi
    done
    
    # to summarize any deleted files or directories at the end of the script uncomment the following line
    #svn diff --summarize -r$revision_from:$revision_to $repository | grep "^[D]"


    Если кому-то интересно, задачу помог решить вот такой shell скрипт
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