Как исправить EOL error?

Question

[kibergile]

Выдаёт ошибку "SyntaxError: EOL while scanning string literal" при выполнении кода:

text = ' 0x61 0x73 0x64 '
text = text.replace('0', R'\')
text = text.replace(' ', '')
print(text)

в чём проблема? неужто replace не хочет использовать "сырые" строки?

Comments

[Влад Григорьев]

сырые строки начинаются с r, а не R

Answer 1

[Сергей Горностаев]

Цитата из документации:

Even in a raw literal, quotes can be escaped with a backslash, but the backslash remains in the result; for example, r"\"" is a valid string literal consisting of two characters: a backslash and a double quote; r"\" is not a valid string literal (even a raw string cannot end in an odd number of backslashes). Specifically, a raw literal cannot end in a single backslash (since the backslash would escape the following quote character). Note also that a single backslash followed by a newline is interpreted as those two characters as part of the literal, not as a line continuation.

Проще говоря, единичный обратный слеш сырой строкой быть не может.