Как такую regex строку превратить в аргумент команды grep?
^(?!127)[0-9]{0,3}\.[0-9]{0,3}\.[0-9]{0,3}\.(?!255)[0-9]{0,9}
grep то toybox
usage: grep [-EFrivwcloqsHbhn] [-ABC NUM] [-m MAX] [-e REGEX]... [-MS PATTERN]... [-f REGFILE] [FILE]...
Show lines matching regular expressions. If no -e, first argument is
regular expression to match. With no files (or "-" filename) read stdin.
Returns 0 if matched, 1 if no match found.
-e Regex to match. (May be repeated.)
-f File listing regular expressions to match.
file search:
-r Recurse into subdirectories (defaults FILE to ".")
-M Match filename pattern (--include)
-S Skip filename pattern (--exclude)
match type:
-A Show NUM lines after -B Show NUM lines before match
-C NUM lines context (A+B) -E extended regex syntax
-F fixed (literal match) -i case insensitive
-m match MAX many lines -v invert match
-w whole word (implies -E) -x whole line
-z input NUL terminated
display modes: (default: matched line)
-c count of matching lines -l show matching filenames
-o only matching part -q quiet (errors only)
-s silent (no error msg) -Z output NUL terminated
output prefix (default: filename if checking more than 1 file)
-H force filename -b byte offset of match
-h hide filename -n line number of match
