ПЕревести синтаксис Mysql в Laravel?

Question

[Analka]

Есть запрос

SELECT t1.user_id 
FROM likes t1
JOIN likes t2 ON t1.user_id = t2.like_user 
             AND t2.user_id = 1
             AND t1.like_user = 1

как мне его записать в Laravel?

пробую так

$users = DB::table(DB::raw('likes t1'))
       ->join(DB::raw('likes t2'), 't1.user_id', '=', 't2.like_user ')
       ->where('t2.user_id', '=', '1')
            ->where(' t1.like_user', '=', '1')->paginate(15);

но выдает

Base table or view not found: 1146 Table 'extremje_dating.DB::raw('likes t1')' doesn't exist (SQL: select count(*) as aggregate from `DB::raw('likes t1')` inner join `DB::raw('likes t2')` on `t1`.`user_id` = `t2`.`like_user ` where `t2`.`user_id` = 1 and ` t1`.`like_user` = 1)

Answer 1

[Adamos]

$users = DB::table('likes AS t1')
       ->join('likes AS t2', 't1.user_id', '=', 't2.like_user ')
       ->where('t2.user_id', '=', '1')
            ->where(' t1.like_user', '=', '1')->paginate(15)