Как правильно запустить Celery?

Question

Павел @BoRzZoY

Celery

Как правильно запустить Celery?

Здравствуйте! Только осваиваю веб после перехода с десктопа.
Нужно реализовать фоновое выполнение задач, для которого выбрал Celery. Сам проект на фреймворке Django, но пока хочу попробовать чисто Celery.

Что я сделал:
- установил celery в виртуальное окружение
- установил rabbitmq
- создал отдельную папку, в которой файл tasks.py и celery.py

Содержимое tasks.py

from celery import Celery
app = Celery('tasks', backend='amqp', broker='amqp://')
@app.tasks
def print_hello():
    print ("Hello")

Содержимое celery.py (то, что нашел в интернете, типо конфиги)

from __future__ import absolute_import, unicode_literals
from celery import Celery
app = Celery('proj',
             broker='amqp://',
             backend='amqp://',
             include=['proj.tasks'])
# Optional configuration, see the application user guide.
app.conf.update(
    result_expires=3600,
)
if __name__ == '__main__':
    app.start()

Запускаю так:
(ENV) root@cs53546:/home/analytics/messages# celery worker -A tasks

Получаю это:

Traceback (most recent call last):
  File "/home/analytics/ENV/bin/celery", line 11, in <module>
    sys.exit(main())
  File "/home/analytics/ENV/lib/python3.5/site-packages/celery/__main__.py", line 14, in main
    _main()
  File "/home/analytics/ENV/lib/python3.5/site-packages/celery/bin/celery.py", line 326, in main
    cmd.execute_from_commandline(argv)
  File "/home/analytics/ENV/lib/python3.5/site-packages/celery/bin/celery.py", line 488, in execute_from_commandline
    super(CeleryCommand, self).execute_from_commandline(argv)))
  File "/home/analytics/ENV/lib/python3.5/site-packages/celery/bin/base.py", line 276, in execute_from_commandline
    argv = self.setup_app_from_commandline(argv)
  File "/home/analytics/ENV/lib/python3.5/site-packages/celery/bin/base.py", line 478, in setup_app_from_commandline
    self.app = self.find_app(app)
  File "/home/analytics/ENV/lib/python3.5/site-packages/celery/bin/base.py", line 500, in find_app
    return find_app(app, symbol_by_name=self.symbol_by_name)
  File "/home/analytics/ENV/lib/python3.5/site-packages/celery/app/utils.py", line 345, in find_app
    sym = symbol_by_name(app, imp=imp)
  File "/home/analytics/ENV/lib/python3.5/site-packages/celery/bin/base.py", line 503, in symbol_by_name
    return imports.symbol_by_name(name, imp=imp)
  File "/home/analytics/ENV/lib/python3.5/site-packages/kombu/utils/imports.py", line 56, in symbol_by_name
    module = imp(module_name, package=package, **kwargs)
  File "/home/analytics/ENV/lib/python3.5/site-packages/celery/utils/imports.py", line 101, in import_from_cwd
    return imp(module, package=package)
  File "/home/analytics/ENV/lib/python3.5/importlib/__init__.py", line 126, in import_module
    return _bootstrap._gcd_import(name[level:], package, level)
  File "<frozen importlib._bootstrap>", line 986, in _gcd_import
  File "<frozen importlib._bootstrap>", line 969, in _find_and_load
  File "<frozen importlib._bootstrap>", line 958, in _find_and_load_unlocked
  File "<frozen importlib._bootstrap>", line 673, in _load_unlocked
  File "<frozen importlib._bootstrap_external>", line 665, in exec_module
  File "<frozen importlib._bootstrap>", line 222, in _call_with_frames_removed
  File "/home/analytics/messages/tasks.py", line 5, in <module>
    @app.tasks
TypeError: 'TaskRegistry' object is not callable

Вопрос:
Что я делаю не так?