Как реализовать выход из приложения, если игрок не находится на одном из pygame.Rect?

Question

[Константин]

Делаю ритм-игру. Игра заключается в том, что надо оставаться на дорожке, по которой двигается игрок.
Вот наглядно: https://drive.google.com/file/d/1KpBerWIb8xXl7wrMo...

Вот код:

import pygame
from pygame.locals import *
import sys
import json

pygame.init()
pygame.mixer.init()

with open('settings.json') as f:
	settings = json.load(f)

resolution = (settings["width"], settings["height"])

screen = pygame.display.set_mode(resolution)
pygame.display.set_caption('Tap Tap Beat - Playing')

clock = pygame.time.Clock()

playerX = 256
playerY = 488
speed = 3

motions = ["up", "left", "right"]
motion = "up"

player = pygame.image.load("player.png")
playerRect = pygame.Rect(playerX, playerY, 48, 48)

point_Up = pygame.image.load("point_up.png")
point_Up = pygame.transform.scale(point_Up, (48, 48))

point_Left = pygame.image.load("point_left.png")
point_Left = pygame.transform.scale(point_Left, (48, 48))

point_Right = pygame.image.load("point_right.png")
point_Right = pygame.transform.scale(point_Right, (48, 48))

rotateMap = [1,0,2]
rotates = 0

gameMap = [
	[0,0,0,0,0,0,0,0],
	[0,0,0,0,0,0,0,0],
	[0,0,4,0,0,0,0,0],
	[0,0,1,0,0,0,0,0],
	[0,0,2,1,3,0,0,0],
	[0,0,0,0,1,0,0,0],
	[0,0,0,0,1,0,0,0],
	[0,0,0,0,1,0,0,0]
]

collisionRects = []

fall = False

for a in range(8):
	for b in range(8):
		if gameMap[a][b] == 1:
			collisionRects.append(pygame.draw.rect(screen, (255, 255, 255), (b*64-8, a*64-8, 64, 64)))
		if gameMap[a][b] == 2:
			collisionRects.append(pygame.draw.rect(screen, (255, 255, 255), (b*64-8, a*64-8, 64, 64)))
		if gameMap[a][b] == 3:
			collisionRects.append(pygame.draw.rect(screen, (255, 255, 255), (b*64-8, a*64-8, 64, 64)))
		if gameMap[a][b] == 4:
			collisionRects.append(pygame.draw.rect(screen, (255, 255, 255), (b*64-8, a*64-8, 64, 64)))

def game():
	global playerX, playerY, rotates, motion, playerRect
	while True:
		clock.tick(60)

		screen.fill((53, 195, 215))

		for event in pygame.event.get():
			if event.type == QUIT:
				pygame.quit()
				sys.exit()
			elif event.type == KEYDOWN:
				if event.key == K_SPACE:
					try:
						motion = motions[rotateMap[rotates]]
						rotates += 1
					except IndexError:
						motion = None

		if motion == motions[0]:
			playerY -= speed
		elif motion == motions[1]:
			playerX -= speed
		elif motion == motions[2]:
			playerX += speed


		for a in range(8):
			for b in range(8):
				if gameMap[a][b] == 1:
					pygame.draw.rect(screen, (255, 255, 255), (b*64-8, a*64-8, 64, 64))
				if gameMap[a][b] == 2:
					pygame.draw.rect(screen, (255, 255, 255), (b*64-8, a*64-8, 64, 64))
					screen.blit(point_Up, (b*64, a*64))
				if gameMap[a][b] == 3:
					pygame.draw.rect(screen, (255, 255, 255), (b*64-8, a*64-8, 64, 64))
					screen.blit(point_Left, (b*64, a*64))
				if gameMap[a][b] == 4:
					pygame.draw.rect(screen, (255, 255, 255), (b*64-8, a*64-8, 64, 64))
					screen.blit(point_Right, (b*64, a*64))

		playerRect = pygame.Rect(playerX, playerY, 48, 48)

		# playerRect = pygame.Rect(playerX, playerY, 48, 48)

		# pygame.draw.circle(screen, (255, 0, 0), (playerX, playerY), 20, 2)
		screen.blit(player, (playerX, playerY))

		pygame.display.flip()
game()

Как сделать так, чтобы при НЕ соприкосновении игрока с дорожкой, к примеру, закрывалась игра?

Answer 1

[Иван Четчасов]

псевдокод:

прог
нач
  алг элемент_жиз_цикла_программы
  нач
    для тчк из getallpoint(trailRect)
    нач
      если не playerRect.collidepoint(nxr) то
      нач
        sys.exit()
      кон
    кон
  кон
  алг getallpoint(rct: Rect = Rect(0, 0, 100, 100))
  нач
    верн: список = []
    для х из промежутка rct.x, rct.x+rct.w
    нач
      для у из промежутка rct.y, rct.y+rct.h
      нач
        добавить [х, у] к верн
      кон
    кон
  вернуть верн
  кон
кон.