Как через sed awk удалить # в 50 и 54 строках?

Question

[Digsecman]

46 #------------------------------------------------------------------------------
47 # CONNECTIONS AND AUTHENTICATION
48 #------------------------------------------------------------------------------

49 # - Connection Settings -

50 #listen_addresses = 'localhost' # what IP address(es) to listen on;
51 # comma-separated list of addresses;
52 # defaults to 'localhost'; use '*' for all
53 # (change requires restart)
54 #port = 5432 # (change requires restart)

и кроме того как вместо localhost вписать свое значение?

Answer 1

[jcmvbkbc]

sed "s/#listen_addresses = 'localhost'/listen_addresses = 'желаемый адрес'/;s/#port = 5432/port = желаемый_порт/"